A block B of mass 4kg is placed on a rough horizontal plane. A time dependent horizontal force f=kt2 acts on the block, k=2N/s2. The frictional force between the block and the plane at t=2 sec is μ=0.2
A
4N
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B
8N
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C
12N
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D
zero
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Solution
The correct option is B8N
F=4t2
F=2t2−4=2
Fmax=μmg
=(0.8)(4)(10)
=32N.
Applied Force F=2t2
at t=2sF=2(2)2=8N
Hence body cannot move and force of friction between block and phase = applied force =8N.