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Question

A block begins to slide down a rough inclined plane of angle 45 and moves 1 m in 42 second. What is the coefficient of friction between the plane and the block? g=10 m/s2

A
0.4
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B
0.5
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C
0.6
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D
0.8
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Solution

The correct option is D 0.8
The said condition can be shown as


From the figure we have
N=mgcos45
f=μN=μmgcos45
So, from force equation we have,
mgsin45f=ma
mgsin45μmgcos45=ma
a=g(sin45μcos45)=10(12μ2) m/s2

Given, total length of the incline s=1 m and time taken, t=42 sec
s=ut+12at2
1=0+12×10(12μ2)(42)2
μ=0.8

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