A block dragged on a smooth plane with the help of a rope which moves with velocity v, as shown in the figure. The horizontal velocity of the block is;

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\frac{v}{s i n θ}

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v s i n θ

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\frac{v}{c o s θ}

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Solution

The correct option is C $v s i n θ$
Given,

Velocity of string $= V$

Horizontal component of Velocity $V_{x} = V sin θ$

The horizontal velocity of the block is $V sin θ$

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A block dragged on a smooth plane with the help of a rope which moves with velocity v, as shown in the figure. The horizontal velocity of the block is;

The correct option is C vsinθGiven, Velocity of string =V Horizontal component of Velocity Vx=Vsinθ The horizontal velocity of the block is Vsinθ

The correct option is C $v s i n θ$
Given,

Velocity of string $= V$

Horizontal component of Velocity $V_{x} = V sin θ$

The horizontal velocity of the block is $V sin θ$