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Question

A block is attached to a spring having equilibrium position at x=0. The block oscillates between x=4 m and x=4 m. Find the change in potential energy stored in the spring when the block moves from x=2 to x=3. Given the spring constant is 5 N/m.

A
12.5 J
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B
32.5 J
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C
37.5 J
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D
10 J
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Solution

The correct option is A 12.5 J
Energy stored when spring is at x=2 m is
U1=12kx2=12×5×22
U1=10 J

Energy stored when spring is at x=3 m is
U2=12kx2=12×5×(3)2
U2=22.5 J

Change in potential energy of the spring =U2U1
=22.510=12.5 J

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