A block is dragged on a smooth plane with the help of a rope which moves with a velocity v as shown in figure. The horizontal velocity of the block is:
A
v
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B
vsinθ
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C
vsinθ
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D
vcosθ
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Solution
The correct option is Bvsinθ
Component of velocity along string must be same,
So, Velocity of m along string =v So, vmsinθ=v⇒vm=vsinθ