Question

A block is dragged on smooth plane with the help of a rope which moves with velocity v. The horizontal velocity of the block is :

• A. v
• B. $\frac{v}{sin\theta }$
• C. $vsin\theta$
• D. $\frac{v}{cos\theta }$

Answer 1

Answer: (C)

$vsin\theta$

Horizontal velocity of the block
Using the triangle formula:
Formula of $sin\theta$
Finding the velocity
$sin\theta =\frac{V}{v}$
Hence horizontal velocity
= $v\times sin\theta$