A block is moving under the influence of a constant force F=3600N. The force acts on the ball for the duration of 0.004h. The average impulse imparted by the force is
A
14400N s
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B
51840N s
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C
0.004N s
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D
2844N s
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Solution
The correct option is B51840N s Average impulse imparted by the force =F.Δt
i.e J=F.Δt
Given, F=3600N Δt=0.004h=3600×0.004s Δt=14.4s
Therefore, J=F.Δt =3600×14.4 =51840N s