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Question

A block is placed on a rough horizontal plane (xz plane) with coefficient of friction is equal to μ. In Y and Z direction constant force mg is applied as shown, and in the X direction a time-varying force F=mgt is applied, where t is time. If block starts moving at time t=1s. Then value of μ is:
1029945_fac4e0484230450aab36ee2113a83cb0.png

A
12
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B
12
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C
13
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D
13
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Solution

The correct option is B 12
At t=1sec
F=mg
So,
mg=μmg+μmgμ=0.5

1157918_1029945_ans_b483fdaac48944318295b2a0e7b86959.png

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