wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A block is placed on an inclined plane of inclination θ. The angle of inclination is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction between the block and the inclined plane is equal to


A

sin θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

cos θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

tan θ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

cot θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

tan θ



As the block moves down the inclined plane at a constant velocity, its acceleration will be zero. Hence, the net force acting on it will be zero.
mg sinθ=μNmg sinθ=μmg cos θμ=tan θ
Hence, the correct choice is (c).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon