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Question

A block is placed on the top of a smooth inclined plane of inclination θ kept on the floor of a lift. When the lift is descending with a retardation a, the block is released. The acceleration of the block relative to the incline is

A
gsinθ
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B
asinθ
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C
(ga)sinθ
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D
(g+a)sinθ
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Solution

The correct option is D (g+a)sinθ
When the lift is descending with a retardation ( negative acceleration)a, the effective value of g is geff=g+a
the component of this acceleration along the inclined plane is
geffsinθ=(g+a)sinθ
Hence,
option (D) is correct answer.

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