A block is projected along a rough horizontal road with a speed of 10 m/s. If the coefficient of kinetic friction is 0.10, then before coming to rest it will travel a distance of

10 m

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30 m

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50 m

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70 m

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Solution

The correct option is D $50 m$
Retardation due to kinetic friction= $- μ g = - 1 m / s^{2}$
Apply third equation of motion
$v^{2} = u^{2} + 2 a s$
$0 = 100 - 2 \times 1 \times s$
$s = 50 m$

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A block is projected along a rough horizontal road with a speed of 10 m/s. If the coefficient of kinetic friction is 0.10, then before coming to rest it will travel a distance of

The correct option is D 50mRetardation due to kinetic friction=−μg=−1m/s2Apply third equation of motion v2=u2+2as0=100−2×1×ss=50m

The correct option is D $50 m$
Retardation due to kinetic friction= $- μ g = - 1 m / s^{2}$
Apply third equation of motion
$v^{2} = u^{2} + 2 a s$
$0 = 100 - 2 \times 1 \times s$
$s = 50 m$