A block is projected along a rough horizontal road with a velocity of 10 m/s. If the coefficient of kinetic friction is 0.1, how far will it travel before coming to rest?

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Solution

u = 10 m/s v = 0. a=μg = deacceleration (-ve)
i.e., v²=u²−2ax
⇒0=(10)²−2×0.1×10×x
⇒x=100/(2×0.1×10)
⇒x=50 m.

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A block is projected along a rough horizontal road with a velocity of 10 m/s. If the coefficient of kinetic friction is 0.1, how far will it travel before coming to rest?

u = 10 m/s v = 0. a=μg = deacceleration (-ve)i.e., v2=u2−2ax⇒0=(10)2−2×0.1×10×x⇒x=100/(2×0.1×10)⇒x=50 m.

u = 10 m/s v = 0. a=μg = deacceleration (-ve)
i.e., v²=u²−2ax
⇒0=(10)²−2×0.1×10×x
⇒x=100/(2×0.1×10)
⇒x=50 m.