A block is shot with an initial velocity of 5m/s on a rough horizontal plane. Find the distance covered by the block till it comes to rest. Given coefficient of friction between the surfaces of contact is 0.1andg=10m/s2.
A
5m
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B
10m
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C
12.5m
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D
25m
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Solution
The correct option is C12.5m The given situation is shown below
The block will be under the impact of frictional force after getting shot. This will cause retardation. Hence, the acceleration of the block is given by F=ma=−f ⇒f=μN ⇒−μN=ma ⇒−μmg=ma a=−μg=0.1×10=−1m/s2
Given, u=5m/s,a=−1m/s2,andv=0 From the equation of motion we have ⇒v2−u2=2as⇒02−52=−2(1)(s) ⇒s=12.5m