A block is sliding down on an inclined plane. The velocity changes at a constant rate from 10 cms−1 to 15 cms−1 in 2 seconds. What is its acceleration?
2.5 cms−2
The motion is depicted below
Here,
final velocity v = 15 cms−1, initial velocity u = 10 cms−1 and time taken t = 2 s
Let 'a' be the acceleration.
From 1st equation of motion,
a=v − ut
a=15 − 102
⇒acceleration=2.5 cms−2