Question

A block is sliding on a rough horizontal surface. If the contact force on the block is $\sqrt{2}$ times the frictional force, the coefficient of friction is:

• A. 0.25
• B. $\frac{1}{\sqrt{2}}$
• C. $\sqrt{2}$
• D. 1

Answer 1

The correct option is B $\frac{1}{\sqrt{2}}$

So, the contact force is normal reaction

So,

$N=\sqrt{2}\times f$

$N=$ normal reaction

$f=$ frictional force

$mg=\sqrt{2}\times \mu \times mg$

$\mu =\frac{1}{\sqrt{2}}$