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Question

A block m2 is loaded onto another block m1 placed on a spring of stiffness k as shown in the figure. If block m2 is suddenly removed, then magnitude of acceleration of block m1 just after the removal of m2 will be:


A
m1m2m1+m2g
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B
(m2m1g)
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C
(m1m2g)
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D
m1+m2m1m2
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Solution

The correct option is B (m2m1g)
Considering the equilibrium of system, just before removal of m2.

FBD before removal of m2:


Here, x= compression in spring

kx=(m1+m2)g(i)
x=(m1+m2)gk

Spring force will remain as it is after removal of m2, because spring will not change its length instantaneously.

FBD after removal of m2:

Applying Newton's 2nd law on block m1 in direction of acceleration:

kxm1g=m1a
(m1+m2)gm1g=m1a
(from (i))

a=(m2m1g)

Hence, block m1 will move with acceleration (m2m1g) upwards.

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