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Question

A block moving with initial velocity u=20 m/s comes to rest after covering distance of 40 m on a rough plane. Find out coefficient of kinetic friction. (Take g=10 m/s2)

A
0.5
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B
0.25
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C
0.75
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D
Data incomplete
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Solution

The correct option is A 0.5
Given,
u=20 m/s
S=40 m
Using eq, v2=u2+2as
0(20)2=2a×40
a=5 m/s2
Since no external force except friction is acting on the block, therefore
Frictional force = ma
= 5m
Also, friction force= μmg
therefore, μmg = 5m
μg=5
μ=5g=0.5

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