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Question

A block of 10Kg is placed on a rough horizontal surface whose cofficient of static friction μs is equal to 0.5. A force of 100N is exerted on the block as shown in the figure. The minimum force that must be applied on the block vertically downwards so that the block doesn't move is
301842_7873c536350842dc982cd54022607265.png

A
100N
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B
150N
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C
200N
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D
225N
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Solution

The correct option is C 100N
m=10kg
Since the friction is a self-adjusting force and it remains between 0 and the maximum frictional force,
So, 0fsμN
1000.5N
1000.5[100+F]
200100+F
F100N
Minimum F = 100 N

276416_301842_ans_fed64ddbd9344996b9f433d243effc6d.png

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