A block of 4kg is suspended from the ceiling through a massless spring of spring constant k=100N/m. If 4kg is replaced by 8kg, what would be the ratio of elongation in 1st case to 2nd case?
A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D0.5 FBD of the block,
For equilibrium, spring force = Weight of the block
Case (1) kx1=m1g⇒x1=m1gk⇒4(10)100=0.4m
Case (2) x2=m2gk=8(10)100=0.8m