A block of 4kg is resting on a rough horizontal plane and is about to move. When a horizontal force of 30n is applied on it find the total contact force exerted by the plane on the block

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Solution

Given
m = 4 kg;
F = 30 N ;
g = 10 ms^-2

N = mg = 4×10 = 40 N

=> R²=N² + F²
so,

R² = (40)² + (30)²

R² =1600+900=2500

R = √2500

R= 50 N( Answer)

Thank you :)

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A block of 4kg is resting on a rough horizontal plane and is about to move. When a horizontal force of 30n is applied on it find the total contact force exerted by the plane on the block

Given m = 4 kg; F = 30 N ; g = 10 ms^-2 N = mg = 4×10 = 40 N => R²=N² + F² so, R² = (40)² + (30)² ​​​​R² =1600+900=2500 R = √2500 R= 50 N( Answer) Thank you :) ​​​

Given
m = 4 kg;
F = 30 N ;
g = 10 ms^-2

N = mg = 4×10 = 40 N

=> R²=N² + F²
so,

R² = (40)² + (30)²

R² =1600+900=2500

R = √2500

R= 50 N( Answer)

Thank you :)