You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Density

A block of al...

Question

A block of aluminium of density 2.75 $g / c m^{3}$ has a volume of 30 $c m^{3}$ . The mass of the block is:

27

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!

82.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

810

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $82.5$ gm
Mass $=$ Density $\times$ Volume
So, Mass of aluminium $= 2.75 \times 30 = 82.5 g m$
Hence, option $C$ is correct.

Suggest Corrections

Similar questions

Q. A vessel contains oil (density = 0.8

g m / c m^{3}

) over mercury (density = 13.6

g m / c m^{3}

). A uniform sphere floats with half its volume immersed in mercury and the other half in oil. The density of the material of sphere in

g m / c m^{3}

is:

Q. A block of iron of density 20 g/cm3 has a volume of 20 cm3. The mass of the block is:

Q. A

b c c

element (atomic mass

65

) has a cell edge of

420 p m

. Calculate its density in

g m s / c m^{3}

Q. The density of a liquid at

100^{0}

C is

8.0

/ c m^{3}

and at

0^{0}

C is

8.4

/ c m^{3}

, the coefficient of cubical expansion of the liquid is?

Two miscible fluids of densities 1.2 gm/cm³ and 1.4 gm/cm³ are mixed with a proportion of their volumes equal to 3:5. Assuming both fluids to be perfectly miscible, what is the density of resulting liquid?

Join BYJU'S Learning Program

A block of aluminium of density 2.75 g/cm3 has a volume of 30cm3. The mass of the block is:

The correct option is C 82.5 gmMass = Density × VolumeSo, Mass of aluminium =2.75×30=82.5 gmHence, option C is correct.

A block of aluminium of density 2.75 $g / c m^{3}$ has a volume of 30 $c m^{3}$ . The mass of the block is:

The correct option is C $82.5$ gm
Mass $=$ Density $\times$ Volume
So, Mass of aluminium $= 2.75 \times 30 = 82.5 g m$
Hence, option $C$ is correct.