wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of density 2000 kg/m3 and mass 10 kg is suspended by a spring stiffness 100 N/m. The other end of the spring is attached to a fixed support. The block is completely submerged in a liquid of density 1000 kg/m3. If the block is in equilibrium position then,


A

the elongation of the spring is 1 cm.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

the magnitude of buoyant force acting on the block is 50N.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

the spring potential energy is 12.5 J.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

magnitude of spring force on the block is greater than the weight of the block.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
B

the magnitude of buoyant force acting on the block is 50N.


C

the spring potential energy is 12.5 J.


At equilibrium

kx=Mg=FB

kx=mg(1σρ)

100(x)=100(110002000)

x=0.5 m

FB=50 N

P.E.=12kx2=12.5 J


flag
Suggest Corrections
thumbs-up
2
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What's with All the Tension in the Room?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon