You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Energy

A block of ic...

Question

A block of ice of mass $50 k g$ is pushed out on a horizontal plane with a velocity of $5 m / s$ . Due to friction it comes to rest after covering a distance of $25 m$ . How much ice will melt?

1 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.50 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.87 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.86 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1.87 g$
Energy with the block of ice $= \frac{1}{2} m v^{2}$
Energy with the block $= \frac{1}{2} \times (50 k g) (5)^{2} = 625 J$
Latent heat of fusion of ice $(L_{f u s i o n})$ = $333.5 J / g$
Melted mass is given by:
$m L_{f u s i o n} = 625 J$
i.e. $m = \frac{625}{L_{f u s i o n}} = 1.87 g$

Suggest Corrections

Similar questions

Q. A block of ice of mass

50 k g

is sliding on a horizontal plane. It starts with speed

5 m / s

and stops after moving through some distance. The mass of ice that has melted due to friction between the block and the surface is:

[Assuming that no energy is lost and latent heat of fusion of ice is

80 c a l / g

J = 4.2 J / c a l

]

Q. A block is shot with an initial velocity of

5 m / s

on a rough horizontal plane. Find the distance covered by the block till it comes to rest. Given coefficient of friction between the surfaces of contact is

0.1 and g = 10 m / s^{2}

A block of mass 10 kg slides with velocity of 10 m/s on a rough horizontal surface. It comes to rest after covering a distance of 50 meters. Find the frictional force.

Q. A person of mass

72 K g

sitting on ice pushes a block of masses of

30 K g

on ice horizontally with a speed of

12 m s^{- 1}

The coefficient of friction between the man and ice and between block and ice in

0.02

g = 10 m s^{- 2}

. the distance between man and the block, when they come to rest is.

Join BYJU'S Learning Program

A block of ice of mass 50 kg is pushed out on a horizontal plane with a velocity of 5 m/s. Due to friction it comes to rest after covering a distance of 25 m. How much ice will melt?

The correct option is C 1.87 gEnergy with the block of ice =12mv2Energy with the block =12×(50kg)(5)2=625JLatent heat of fusion of ice (Lfusion) = 333.5J/gMelted mass is given by:mLfusion=625Ji.e. m=625Lfusion=1.87g

A block of ice of mass $50 k g$ is pushed out on a horizontal plane with a velocity of $5 m / s$ . Due to friction it comes to rest after covering a distance of $25 m$ . How much ice will melt?