Question

A block of iron has dimensions $2m\times 0.5m\times 0.25m$. The density of iron is $7.8gc{m}^{-3}$ Find the mass of block.

Answer 1

Given , $I$ = $2m$
$b$ = $0.5m$
$h$= $0.25m$
Density of iron = $7.8gc{m}^3$ = $7.8\times 1000kg{m}^{-3}$ = $7800kg{m}^{-3}$
Volume of block = $l\times b\times h$
= $2\times 0.5\times 0.25$ = $0.25m^3$
From relation d= $\frac{M}{V}$
$\therefore$ Mass of iron block $M=V\times d$
= $0.25\times 7800kg{m}^3$
= $1950kg$