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Question

A block of mass 0.1kg is held against a wall applying a horizontal force of 5N on the block. If the coefficient of friction between the block and the wall is 0.5. the magnitude of the friction force acting on the block is

A
2.5N
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B
0.98N
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C
4.9N
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D
0.49N
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Solution

The correct option is C 0.98N
Limiting value of frictional force,

fmax=μN=.5×5=2.5N

Now, value of mg=0.1×9.8=0.98N

fmax>mg

then frictional force acting on block is

f=mg=0.98N

983709_990362_ans_cfedb45847bd43fdbd650f771ea841de.png

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