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Question

A block of mass 0.1kg is held against a wall by applying a horizontal force on 5N on it. If μs between the wall and the block is 0.5 the magnitude of the frictional force acting on the block is :

A
0.98N
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B
0.49N
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C
4.9N
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D
2.5N
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Solution

The correct option is C 0.98N
Nr=5kg
μs=.5
Limiting friction force=μNr=.5×5=2.5N
Flimting>weight
So the block is at rest:
Fs=W=0.1×9.8
=0.98 N
514358_476513_ans_429ad91891d647e584e7729209e765be.png

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