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Standard X

Physics

Power

A block of ma...

Question

A block of mass $0.1 k g$ is pressed against a wall with a horizontal force of $5 N$ as shown in the figure. If the coefficient of friction between the wall and the block is $0.5$ then the frictional force acting on the block will be $(g = 9.8 m / s^{2})$ :

9.8 N

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2.5 N

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0.98 N

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0.49 N

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Solution

The correct option is C $0.98 N$
limiting friction= $μ \times 5 = 0.5 \times 5 = 2.5 N$
weight acting downwards=mg= $0.1 \times 9.8 = 0.98 N$
therefore frictional force = force acting $= 0.98 N$

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A block of mass 0.1 kg is pressed against a wall with a horizontal force of 5N as shown in the figure. If the coefficient of friction between the wall and the block is 0.5 then the frictional force acting on the block will be (g=9.8 m/s2):

The correct option is C 0.98 Nlimiting friction=μ×5=0.5×5=2.5Nweight acting downwards=mg=0.1×9.8=0.98Ntherefore frictional force = force acting=0.98N

A block of mass $0.1 k g$ is pressed against a wall with a horizontal force of $5 N$ as shown in the figure. If the coefficient of friction between the wall and the block is $0.5$ then the frictional force acting on the block will be $(g = 9.8 m / s^{2})$ :

The correct option is C $0.98 N$
limiting friction= $μ \times 5 = 0.5 \times 5 = 2.5 N$
weight acting downwards=mg= $0.1 \times 9.8 = 0.98 N$
therefore frictional force = force acting $= 0.98 N$