Question

A block of mass 0.50 kg is moving with a speed of 2.00 ${ms}^{-1}$ on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

• A. 1.00 J
• B. 0.67 J
• C. 0.34 J
• D. 0.16 J

Answer 1

The correct option is B 0.67 J

R.E.F image

By momentum conservation

$0.5\times 2=1.5\times v$

$v=\frac{2}{3}m/sec$

Initial Energy =$\frac{1}{2}\times 0.5\times (2{)}^2$

=1 joule .

Final Energy =$\frac{1}{2}\times 1.5\times (\frac{2}{3}{)}^2$

=1/3 joule .

Loss= Initial-Final

$=1-\frac{1}{3}=\frac{2}{3}=0.67J$

option (B)