Question

A block of mass $0.5kg$ is moving with a speed of $2.0m/s$ on smooth surface. It strikes another mass of $1.0kg$ and then they move together as a single body. The energy loss during collision is (in J)

• A. $0.16$
  
• B. $0.67$
  
• C. $1.0$
  
• D. $6.7$
  

Answer 1

The correct option is B $0.67$

Given ; $m_1=0.5kg$, $u_1=2.0m/s$, $m_2=1.0kg$ and $u_2=0m/s$

Since both the mass move as a single body after collision, so it is a perfectly inelastic collision.

Loss in kinetic energy is a perfectly inelastic collision is given by $\Delta K.E=\frac{1}{2}\frac{m_1{m}_2}{m_1+m_2}(u_1-u_2{)}^2$

$\therefore$ $\Delta K.E=\frac{1}{2}\frac{\left(0.5\right)\left(1.0\right)}{(0.5+1.0)}(2.0-0{)}^2=0.67J$