A block of mass 0.5kg rests against a wall exerting a horizontal force of 10N on the wall. If the coefficient of friction between the wall and the block is 0.5 then the frictional force acting on the block will be:
A
49.9N
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B
9.8N
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C
5N
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D
0.49N
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Solution
The correct option is C5N
Now,
Given, N=10 Newtons
μ=0.2
Frictional force is Nμ
=(0.5)(10)
=5 Newtons
Now the downward force =0.5g
=5 Newtons
So this is equal to the maximum possible frictional force acting.