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Question

A block of mass 0.5kg rests against a wall exerting a horizontal force of 10N on the wall. If the coefficient of friction between the wall and the block is 0.5 then the frictional force acting on the block will be:

A
49.9N
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B
9.8N
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C
5N
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D
0.49N
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Solution

The correct option is C 5N
Now,

Given, N=10 Newtons

μ=0.2

Frictional force is Nμ

=(0.5)(10)

=5 Newtons

Now the downward force =0.5 g

=5 Newtons

So this is equal to the maximum possible frictional force acting.

Hence, frictional force =5 Newtons

1428970_136916_ans_8737403622ee48b9a638ddb5e4082a9c.png

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