Question

A block of mass 1 gm executes an oscillatory motion (sliding) on a concave surface of radius of curvature 2m. If the particle starts its motion from a point at a height of I cm from the horizontal and the coefficient of friction is 0.01 , then the total distance covered by the particle before it comes to rest, will be (approx)

• A. 5.001 m
• B. 0,015 m
• C. 1.005 m
• D. none of these

Answer 1

The correct option is C 1.005 m

$\begin{array}{c}Lossinmechanicalenergy=workdoneagainstfriction\\ mhg=\mu mg\cos \theta \times s\\ s=\frac{h}{\mu g\cos \theta }=\frac{1\times {10}^{-2}}{0.01\times 10\times \frac{2-h}{2}}\\ =1.005m\end{array}$

Hence,

option $C$ is correct answer.