A block of mass 1 kg is moving down the inclined plane with cons†an t velocity f 10 m/s . if angle of inclination is 37^° then coefficient of kinetic friction between the inclined plane and the block is

Open in App

Solution

Suggest Corrections

Similar questions

Q. Block of mass

10 k g

is moving on an inclined plane with constant velocity

10 m / s

. The coefficient of kinetic friction between the incline plane and block is:

Q. A block of mass

m

slides down an inclined plane of slope angle

θ

with constant velocity. Now, same block is projected up an inclined plane with an initial velocity

u

. If the coefficient of kinetic friction between the block and the plane is

μ

, the distance up to which the block will rise up the plane, before coming to rest is :-

Q. A block of mass

m

is kept on an inclined plane inside a lift moving down with acceleration of

2 {m/s}^{2}

. What should be the coefficient of friction between block and inclined plane to let the block move down with constant velocity relative to lift?
(Take

g = 10 {m/s}^{2}

)

A block is placed on an inclined plane of inclination $θ$ . The angle of inclination is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction between the block and the inclined plane is equal to

Q. A block slides down a curved frictionless surface of height

12 m

and then moves up a rough inclined plane of angle of inclination

45^{o}

. If the coefficient of kinetic friction between the block and the inclined plane is

0.2

, the maximum height reached by the block is:

Join BYJU'S Learning Program