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Question

A block of mass 1kg is pushed against a rough vertical wall with a force of 20N, coefficient of static friction being 14. Another horizontal force of 10N is applied on the block in a direction? If no, find the frictional force exerted by the wall on the block. (g= 10m/s2).

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Solution

Normal reaction on the block from the wall will be N=F=20N
Therefore, limiting friction fL=μN=(14)(20)=5N
Weight of the block is
W=mg=(1)(10)=10N
A horizontal force of 10 N is applied to the block. The resultant of these two forces will be 102 N in the direction shown in figure. Since, this resultant is greater than the limiting friction. The block will move in the direction of Fnet with acceleration a=FnetfLm=10251=9.14m/s2

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