A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is $5 m s^{- 2}$ , the frictional force acting on the block is ...............N.

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Solution

Here, We know that
limiting friction, $f = μ m g \Rightarrow$
We have,
$μ = 0.6, m = 1 k g, g = 9.8 {m s}^{- 2}$
$∴$ $f = (0.6 \times 1 \times 9.8) = 5.88 N$
Applied force $\Rightarrow F = m a = 1 \times 5 = 5 N$
As $F < f$ , so force of friction $= 5$ N

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A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5ms−2, the frictional force acting on the block is ...............N.

Here, We know thatlimiting friction, f=μmg⇒We have,μ=0.6,m=1kg,g=9.8ms−2∴ f=(0.6×1×9.8)=5.88NApplied force ⇒F=ma=1×5=5NAs F<f, so force of friction =5N

A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is $5 m s^{- 2}$ , the frictional force acting on the block is ...............N.

Here, We know that
limiting friction, $f = μ m g \Rightarrow$
We have,
$μ = 0.6, m = 1 k g, g = 9.8 {m s}^{- 2}$
$∴$ $f = (0.6 \times 1 \times 9.8) = 5.88 N$
Applied force $\Rightarrow F = m a = 1 \times 5 = 5 N$
As $F < f$ , so force of friction $= 5$ N