A block of mass 1 kg lying on the floor is subjected to a horizontal force given by F=2sinωt newtons. The coefficient of friction between the block and the floor is 0.25. The acceleration of the block will be:
A
positive and uniform
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B
positive and nonuniform
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C
zero
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D
depending on the value of ω
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Solution
The correct option is C zero For a sinusoidal force given by F=2sinωt, the maximum force that can be applied is its amplitude which is 2N. The frictional force that can occur between the block and the floor is f=μmg=0.25×1kg×10ms−2=2.5N Since the force applied is not more than the force of friction F<f, the block will not move, hence its acceleration will be zero.