A block of mass $1 k g$ moving at a speed of $2.5 m / s$ collides with another block of mass $0.5 k g$ . If both the blocks come to rest after collision what was the velocity of the $0.5 k g$ block before the collision?

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Solution

After collision momentum will be zero by momentum conservation.
$m_{1} v_{1} + m_{2} v_{2} = 0 1 \times 2.5 + 0.5 v_{2} = 0 v_{2} = \frac{- 2.5}{0.5} = - 5 m / s$

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A block of mass 1 kg moving at a speed of 2.5 m/s collides with another block of mass 0.5 kg. If both the blocks come to rest after collision what was the velocity of the 0.5 kg block before the collision?

After collision momentum will be zero by momentum conservation.m1v1+m2v2=01×2.5+0.5v2=0v2=−2.50.5=−5m/s

A block of mass $1 k g$ moving at a speed of $2.5 m / s$ collides with another block of mass $0.5 k g$ . If both the blocks come to rest after collision what was the velocity of the $0.5 k g$ block before the collision?

After collision momentum will be zero by momentum conservation.
$m_{1} v_{1} + m_{2} v_{2} = 0 1 \times 2.5 + 0.5 v_{2} = 0 v_{2} = \frac{- 2.5}{0.5} = - 5 m / s$