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Question
A block of mass 1 kg slides down a curved track which forms one quadrant of a circle of radius 1 m as shown in figure. The speed of the block at the bottom of the track is v=2 ms−1. The work done by the force of friction is (Take g=10 ms−2 )
A block of mass 1 kg slides down a curved track which forms one quadrant of a circle of radius 1 m as shown in figure. The speed of the block at the bottom of the track is v=2 ms−1. The work done by the force of friction is (Take g=10 ms−2 )
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Solution
The correct option is B -8 J
Work done by friction =Ef−Ei
12mv2−mgh
where m=1 kg, v=2m/s2, h=1 m
=12×1×(2)2−1×10×1
=−8J
Work done by friction =Ef−Ei
12mv2−mgh
where m=1 kg, v=2m/s2, h=1 m
=12×1×(2)2−1×10×1
=−8J
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