A block of mass 1kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a=5m/s2
Let N be the normal reaction between the block and the wedge. Then (g=10m/s2)
A
N=5√5newton
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B
N=15newton
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C
tanθ=12
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D
tanθ=2
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Solution
The correct option is Ctanθ=12 Solving from wedge's frame ∴Nsinθ=ma……(i)
and Ncosθ=mg……(ii) tanθ=ag=510=12 ⇒N=masinθ=1(5)1√5 ⇒N=5√5N