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Question

A block of mass 1 kg is placed on a rough incline as shown. The coefficient of friction between block and incline is 0.4. The acceleration of block is [g=10 ms2,3=1.7]

A
Zero
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B
1.6 ms2
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C
6.5 ms2
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D
5 ms2
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Solution

The correct option is B 1.6 ms2
Force on the block = mgsinθ
=1×10×12=5 N
Limiting friction = μmgcosθ
=0.4×1×10×32
=23
3.4 N, as 3=1.7 given
F>fL (body slips)
Net force ma=mgsinθμmgcosθ
53.4=a
a=1.6 m/s2

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