Question

A block of mass $10kg$ is held against a vertical wall by applying a horizontal force of $50N$.The coefficient of friction is 0.2 between the block and the wall. What is the frictional force acting? (Take acceleration due to gravity, $g=10m/s^2$)

• A. 104 N
• B. 10 N
• C. 30 N
• D. 80 N

Answer 1

The correct option is B

10 N

Given, normal reaction, N = Force applied = $50N$

Frictional force = Coefficient of friction $\times$ Normal reaction = $0.2\times 50=10N$