wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass 10Kg is placed on a rough horizontal table whose coefficient of static friction μs is equal to 0.5. A Force F acting on the block at angle of 37 is gradually increased from zero. Determine whether the block will first slide or lift up?
302131_e26927e68f4c4ae98fe3de3dcb55c551.png

Open in App
Solution

There is minimum a magnitude of forces required, both in horizontal and vertical direction, either to slide or lift up the block. The block will first slide or lift up would depend upon which minimum magnitude of force is lesser.
For block to start lifting up, in vertical direction
Fsin37+NMg0
N becomes zero on just lifting condition.
Flift10g3/5
Flift5003N
For horizontal direction to start sliding
Fcos37μsN
Fcos37>0.5[10gFsin37](N=10gFsin37)
Hence
fslide>50cos37+0.5sin37
fslide>50011N
Flift>5003N
fslide<Flift
Therefore the block will begin to slide before lifting.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon