The correct option is B 0.2
From the given data we can say that the acceleration of the block is zero since it is moving at constant speed.
Given, mass of the block m=10 kg and the applied external force F=19.6 N
Let f be the friction force acting on the block
⇒ F−f=ma
⇒ F−f=0⇒ F=f=μmg
⇒ 19.6=μ(10g)
or, μ=19.610×9.8=0.2