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Byju's Answer

Standard IX

Physics

Second Law of Motion

A block of ma...

Question

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2 m/ $s^{2}$ . Kinetic friction force acting on block is (take g = 10 m/ $s^{2}$ )

10 N

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30 N

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50 N

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50 \sqrt{3}

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Solution

The correct option is B 30 N
$a_{d o w n} = 2 m / s a_{d o w n} = g s i n 30 - μ g c o s 30 f = μ m g c o s 30 2 = \frac{g}{2} - \frac{f}{m} \frac{f}{m} = 5 - 2 = 3 f = 10 \times 3 = 30 N$

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Similar questions

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A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2 m/s2. Kinetic friction force acting on block is (take g = 10 m/s2)

The correct option is B 30 Nadown=2m/sadown=gsin30−μgcos30f=μmgcos302=g2−fmfm=5−2=3f=10×3=30N

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2 m/ $s^{2}$ . Kinetic friction force acting on block is (take g = 10 m/ $s^{2}$ )

The correct option is B 30 N
$a_{d o w n} = 2 m / s a_{d o w n} = g s i n 30 - μ g c o s 30 f = μ m g c o s 30 2 = \frac{g}{2} - \frac{f}{m} \frac{f}{m} = 5 - 2 = 3 f = 10 \times 3 = 30 N$