Question

A block of mass 10 kg is suspended by three strings as shown in the figure. The tension$T_2$ is:

Answer 1

We know that,

According to figure

$T_3\sin {60}^0=T_2\sin {30}^0$

$T_3=\frac{T_2}{\sqrt{3}}$

Now,

$T_2\cos {30}^0+T_3\cos {60}^0=T_1$

$\frac{\sqrt{3}{T}_2}{2}+\frac{T_2}{\sqrt{3}}\times \frac{1}{2}=100$

$\frac{4T_2}{2\sqrt{3}}=100$

$T_2=50\sqrt{3}N$

Hence, the tension $T_2$ is $50\sqrt{3}N$