A block of mass 10 kg is suspended through two light springs which are balanced as shown in the figure. Then

both the scales will read 10 kg.

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both the scales will read 5 kg.

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the upper scale will read 10 kg and the lower one zero.

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the readings may be of any value, but their sum will be 10 kg.

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Solution

The correct option is A both the scales will read 10 kg.
As in Equilibrium.
From the FBD of the mass and spring balance,
$10 g = T T = T_{1} T_{1} = T_{2} \Rightarrow T_{1} = T_{2} = T = 10 g N$
Therefore both scales will read $\frac{10 g}{g} = 10 k g$ .

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Q. A block of mass 10 kg is suspended from two light spring balances, as shown in the figure.
Figure

(a) Both the scales will read 10 kg.
(b) Both the scales will read 5 kg.
(c) The upper scale will read 10 kg and the lower zero.
(d) The readings may be anything but their sums will be 10 kg.

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A block of mass 10 kg is suspended through two light springs which are balanced as shown in the figure. Then

The correct option is A both the scales will read 10 kg.As in Equilibrium. From the FBD of the mass and spring balance, 10g=TT=T1T1=T2⇒T1=T2=T=10g N Therefore both scales will read 10gg=10 kg.

The correct option is A both the scales will read 10 kg.
As in Equilibrium.
From the FBD of the mass and spring balance,
$10 g = T T = T_{1} T_{1} = T_{2} \Rightarrow T_{1} = T_{2} = T = 10 g N$
Therefore both scales will read $\frac{10 g}{g} = 10 k g$ .