Question

A block of mass 10 kg lying on a smooth horizontal surface is being pulled by means of a rope of mass 2 kg. If a force of 36N is applied at the end of the rope, the tension at the mid point of the rope is:

• A. 33 N
• B. 30 N
• C. 24 N
• D. 12 N

Answer 1

The correct option is A 33 N

The correct option is A

Given,

Block of mass is $10kg$

Rope of mass is $2kg$

$F=36N$

So,

At midpoint A of the rope

$F=ma$

$36=(2+10)a$

$a=\frac{36}{12}=3m/s^2$

Now,

$36-T_A=\frac{m}{2}\times a$

$36-T_A=\frac{2}{2}\times 3$

$T_A=36-3=33N$

Where $T_A$ is the Tension at point A