A block of mass 10 kg placed on rough horizontal surface having coefficient of friction = 0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be : -
A
10 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
15 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.5 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 5 m/s2 In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)
f=μN=μmg=0.5×10×10=50N
So, net force acting on the block in horizontal direction = 100 N-50 N = 50 N
acceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms−2