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Question

A block of mass 10 kg placed on rough horizontal surface having coefficient of friction = 0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be : -

A
10 m/s2
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B
5 m/s2
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C
15 m/s2
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D
0.5 m/s2
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Solution

The correct option is B 5 m/s2
In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)
f=μN=μmg=0.5×10×10=50N
So, net force acting on the block in horizontal direction = 100 N-50 N = 50 N
acceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms2

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