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Elastic Potential Energy

A block of ma...

Question

A block of mass 10 kg.

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Solution

In this case work done is zero because force and displacement are perpendicular (Normal-Force)

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Similar questions

Q. The binding energy per nucleon of

_{5} B^{10}

8.0

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9.11 \times 10^{- 31}

1.67 \times 10^{- 27}

Q. The mass defect of nuclear reaction :

_{4} B e^{10} \to_{5} B^{10} + e^{-}

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