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Question

A block of mass 10 kg is pressed against a vertical wall. If the coefficient of friction between the wall and the block is 0.2, then what is the minimum force that should be applied on the block so that does not fall to the ground?


A
500 N
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B
400 N
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C
600 N
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D
555.5 N
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Solution

The correct option is A 500 N
By the FBD of the block we get,

The force F is applied against the wall, which produces a normal reaction N. Frictional force arises due to this reaction force and counters the weight of the block.
Hence for equillibrium,

N=F
μN=mg
μF=mgF=mgμ=1000.2=500 N
Hence a force of 500 N has to be applied to keep the block in equilibrium.

Hence option A is the correct answer

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