A block of mass 10kg is suspended from a string of length 4m. When pulled by a force F along the horizontal from its midpoint, upper half of the string makes an angle 45∘ with the vertical. The value of F is
A
100N
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B
90N
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C
75N
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D
70N
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Solution
The correct option is A100N
System is in equilibrium. Hence, ∑Fy=0 Tcos45∘−100=0
or T√2=100 .....(i)
and ∑Fy=0 Tsin45∘−F=0
or T√2=F ....(ii)
From eqn (i) and (ii) F=100N